Multiple choice

In each of the given question below, there are two equations as I and II. You have to solve both equations and give answer- I. (x^2 + 3x – 4 = 0) II. (3y^2 – 10y + 8 = 0)

  1. If x > y

  2. If x < y

  3. If x ≥ y

  4. If x ≤ y

  5. If x = y or no relation between x and y can be established.
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Solving equation I: x² + 3x - 4 = 0 factors to (x+4)(x-1) = 0, giving x = -4 or x = 1. Solving equation II: 3y² - 10y + 8 = 0 factors to (3y-4)(y-2) = 0, giving y = 4/3 or y = 2. Comparing all values: both y values (2, 4/3) are greater than both x values (-4, 1), so x < y is correct.

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