Multiple choice

In each of the following questions two equations are given. You have to solve them and give answer - ( (I) -x^2 + 4x + 12 = 0 ) ( (II) 4y^2 – 4y + 1 = 0 )

  1. If x < y

  2. If x > y

  3. If x ≤ y

  4. If x ≥ y

  5. If x = y or Relationship cannot be determined
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

For -x² + 4x + 12 = 0, multiply by -1: x² - 4x - 12 = 0, so (x-6)(x+2) = 0, giving x = 6 or x = -2. For 4y² - 4y + 1 = 0, this is (2y-1)² = 0, so y = 0.5. Comparing: if x = 6, x > y (6 > 0.5); if x = -2, x < y (-2 < 0.5). Since x can be greater or less than y depending on which root we take, the relationship cannot be determined.

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