A volvo bus travels with 80 km/hr and stoppage of 10 min. after every hour and a normal bus travels with 50km/h and stoppage of 6 min after every 50km. If both bus starts together then find the distance travelled by slower bus in the time in which faster bus travels 400km:

Volvo: 80 km/hr with 10 min stop after every hour. For 400 km: 400/80 = 5 hours driving time. Stops: after hours 1, 2, 3, 4 = 4 stops × 10 min = 40 min. Total time = 5 hr 40 min = 340 min. Normal bus: 50 km/hr with 6 min stop after every 50 km. In 340 min, it travels: 50 km in 60 + 6 = 66 min, another 50 km in 66 min (total 132 min, 100 km). Remaining time = 340 - 132 = 208 min. 50 km in 66 min uses 66 min, leaving 142 min for 50 km? Actually in remaining 208 min: next 50 km in 66 min (total 198 min, 150 km). Remaining 142 min. Next segment: can travel 50 km in 66 min (total 264 min, 200 km) but we only have 142 min. In 142 min: first 60 min covers 50 km (total 258 min, 250 km) - no, that exceeds. So in remaining 142 min: 60 min driving covers 50 km, but we have 142 - 60 = 82 min for driving. Distance in 82 min = 82/60 × 50 = 68.33 km. Total distance = 200 + 68.33 = 268.33 km. That's not matching option B (258.33). Let me recalculate: 340 min available. Normal bus covers 50 km in 66 min. 340/66 = 5.15 segments. 5 segments = 5 × 50 = 250 km in 5 × 66 = 330 min. Remaining 10 min can cover 10/60 × 50 = 8.33 km. Total = 258.33 km. Yes! This matches option B.