Multiple choice

$I. (3x^2 + 14x + 15 = 0) II. (3y^2 – 13y + 14 = 0)$ Solve both the equations and determine the relationship between x and y.

  1. If x > y

  2. If x < y

  3. If x = y or the relationship between x and y can’t be established.

  4. If x ≥ y

  5. If x ≤ y
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Solving 3x² + 14x + 15 = 0 gives x = -5/3 or x = -3. Solving 3y² - 13y + 14 = 0 gives y = 7/3 or y = 2. Comparing all possible values: all x values (-1.67, -3) are less than all y values (2.33, 2). Therefore, x < y is correct.

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