Multiple choice

In each of these question, two equations (I) and (II) are given. You have to solve both the equations and give answer.(I. 42x^{2} + 378x - 1512 = 0\II. 84y^{2} + 262y - 420 = 0)

  1. x > y

  2. x < y

  3. x ≤ y

  4. x ≥ y

  5. x = y or relationship cannot be established
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Simplify first equation: 42x² + 378x - 1512 = 0 gives x² + 9x - 36 = 0, roots are x = 3, x = -12. Second equation: 84y² + 262y - 420 = 0. The roots are approximately y ≈ 0.337 and y ≈ -14.832. Since x = 3 > both y values but x = -12 < both y values, the relationship cannot be established.

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