Multiple choice

In each of the following questions two equations are given. You have to solve them and give answer - (I) (a^2 + a = 56) (II) (b^2 - 17b + 72 = 0)

  1. If a < b

  2. If a > b

  3. If a ≤ b

  4. If a ≥ b

  5. If a = b or relationship can not be determined
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A Correct answer
Explanation

Equation I: a² + a - 56 = 0 gives a = [-1 ± √(1 + 224)]/2 = [-1 ± 15]/2, so a = 7 or a = -8. Equation II: b² - 17b + 72 = 0 gives b = [17 ± √(289 - 288)]/2 = [17 ± 1]/2, so b = 9 or b = 8. For a = -8, a < both b values. For a = 7, a < both b values. Thus a < b always.

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