Multiple choice

In the following question two equations numbered I and II are given. You have to solve both the equations and Give answer: I. (12a^2 + 11a + 12 = 10a^2 + 22a) II. (13b^2 – 18b + 3 = 9b^2 – 10b)

  1. If a > b

  2. If a ≤ b

  3. If a < b

  4. If a ≥ b

  5. If a = b or no relationship between a and b can be established
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

For equation I: 2a² - 11a + 12 = 0 factors to (2a-3)(a-4) = 0, giving a = 3/2 or a = 4. For equation II: 4b² - 8b + 3 = 0 factors to (2b-3)(2b-1) = 0, giving b = 3/2 or b = 1/2. Since a can be 3/2 or 4 and b can be 3/2 or 1/2, the relationship is a ≥ b (a is always greater than or equal to b).

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