Multiple choice

In the following question two equations numbered I and II are given. You have to solve both the equations and give answer. $I. (9x^2 - 33x + 28 = 0)$ $II. (6y^2 - 25y + 25 = 0)$

  1. x > y

  2. x < y

  3. x ≥ y

  4. x ≤ y

  5. x = y or relation cannot be established
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Solving equation I: 9x²-33x+28=0 factors as (3x-4)(3x-7)=0, so x=4/3 or x=7/3. Solving equation II: 6y²-25y+25=0 factors as (2y-5)(3y-5)=0, so y=5/2 or y=5/3. Comparing values: x=1.33 or 2.33, y=2.5 or 1.67. When x=4/3 and y=5/2, xy. Since x can be greater or less than y depending on which roots we choose, no definite relation can be established.

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