Multiple choice

In the following question two equations numbered I and II are given. You have to solve both the equations and give answer thereof. I. (x^2 + 3x + 2 = 0) II. (2y^2 = 5y)

  1. $\(x > y\)$
  2. $\(x \ge y\)$
  3. $\(x < y\)$
  4. $\(x \le y\)$

  5. x = y, or relation cannot be established
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Equation I: x²+3x+2 = (x+1)(x+2) = 0, so x = -1, -2. Equation II: 2y²-5y = y(2y-5) = 0, so y = 0, 2.5. Compare: All x values (-1, -2) are less than all y values (0, 2.5). Therefore x < y. Option C correct.

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