Multiple choice

In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer: (I. 5x^2 - 27x + 36 = 0 ) (II. y^2 - 2y + 2 = 0)

  1. x > y

  2. x ≥ y

  3. x < y

  4. x ≤ y

  5. x = y or relation can’t be established
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Equation I: 5x^2 - 27x + 36 = 0 → (5x-12)(x-3)=0 → x = 2.4 or 3. Equation II: y^2 - 2y + 2 = 0 → discriminant = 4 - 8 = -4 < 0. No real roots for y. Since y has imaginary roots while x has real roots, no relation can be established between real x and non-real y.

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