Multiple choice

In the following question, there are two equations. Solve the equations and answer accordingly. (I. \quad 2x^2 - 7x + 5 = 0 ) (II. \quad 2y^2 + 4y - 6 = 0)

  1. X > Y

  2. X < Y

  3. X ≥ Y

  4. X ≤ Y

  5. X=Y or No relation can be established
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

From equation I: 2x² - 7x + 5 = 0 factors to (2x - 5)(x - 1) = 0, so x = 1 or x = 5/2. From equation II: 2y² + 4y - 6 = 0 simplifies to y² + 2y - 3 = 0, which factors to (y + 3)(y - 1) = 0, so y = -3 or y = 1. Comparing all combinations: x = 1, y = 1 gives x = y. x = 5/2, y = -3 gives x > y. x = 5/2, y = 1 gives x > y. x = 1, y = -3 gives x > y. Since x is never less than y, X ≥ Y is correct.

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