Multiple choice

From a solid cylinder of height 10 cm. and radius of the base 6 cm. a cone of same height and same base is removed. The volume of the remaining solid is - 10 सेमी. ऊँचाई और 6 सेमी. त्रिज्या के आधार वाले एक ठोस बेलन से उसी ऊँचाई और उसी जैसा आधार वाला एक शंकु निकाल लिया गया है। तो शेष बचे ठोस का आयतन कितना रह गया है?

  1. 240π cm/सेमी3

  2. 2580π cm/सेमी3

  3. 620π cm/सेमी3

  4. 360π cm/सेमी3
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Cylinder volume = πr²h = π × 6² × 10 = 360π. Cone volume = (1/3)πr²h = (1/3)π × 6² × 10 = 120π. Remaining volume = 360π - 120π = 240π. The cone is exactly one-third of the cylinder, so remaining is two-thirds. Option B is much larger, option C and D don't match.

Keep practicing — related questions