In each of the following questions two equations are given. Solve these equations and give answer : (i) (x^2 - 5(\sqrt{2} + \sqrt{5})x + 25\sqrt{10} = 0) (ii) (y^2 - \sqrt{2}(\sqrt{3} + 2\sqrt{2})y + 4\sqrt{6} = 0)

For equation (i): Use quadratic formula or factor. The quadratic is x^2 - 5(√2+√5)x + 25√10 = 0. By Vieta's formulas, sum = 5(√2+√5), product = 25√10. The roots are 5√2 and 5√5 (approximately 7.07 and 11.18). For equation (ii): y^2 - √2(√3+2√2)y + 4√6 = 0. Roots are 2√2 and 2√3 (approximately 2.83 and 3.46). Both roots of x are greater than both roots of y, so x > y always. Option B is correct.