In the following questions two equations I and II are given. You have to solve both the equations and give answer. $(\text{(I)} x^2 – 3.3x – 2.6 = 0 )(\text{(II)} y^2 + 3y + 2 = 0)$

Equation I: x² - 3.3x - 2.6 = 0. Using quadratic formula: x = [3.3 ± √(10.89 + 10.4)]/2 = [3.3 ± √21.29]/2 = [3.3 ± 4.614]/2. Solutions: x₁ ≈ 3.957, x₂ ≈ -0.657. Equation II: y² + 3y + 2 = 0 factors as (y+1)(y+2) = 0. Solutions: y = -1, -2. Comparison: x₁ (3.957) > y values, but x₂ (-0.657) > y values? Actually -0.657 > -1 and -0.657 > -2, so both x solutions are greater than both y solutions. However, the question asks about x and y as values from these equations. Since we have multiple possible values for both x and y, and the relationship depends on which specific values we compare, the relationship cannot be uniquely determined from the given information alone.