Multiple choice

In the following questions, two equations I and II are given. You have to solve both the equations and give answer. (I: 5x^2 + 19x + 12 = 0 ) (II: 32y^2 - 28y + 3 = 0)

  1. X > Y

  2. X ≥ Y

  3. X < Y

  4. X ≤ Y

  5. X = Y or the relation cannot be established

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Equation I: 5x² + 19x + 12 = 0. Discriminant = 361 - 240 = 121. x = (-19 ± 11)/10. So x = -8/10 = -0.8 or x = -30/10 = -3. Equation II: 32y² - 28y + 3 = 0. Discriminant = 784 - 384 = 400. y = (28 ± 20)/64. So y = 48/64 = 3/4 = 0.75 or y = 8/64 = 1/8 = 0.125. Comparing: x = -0.8 or -3, y = 0.125 or 0.75. All x values are less than all y values. Therefore X < Y.