Multiple choice

The age of father E years ago was thrice the age of his son. F years hence, father’s age will be twice that of his son. The ratio of their present ages is 7:3. Find the value of E and F?

  1. E= 10, F=10

  2. E= 20, F=10

  3. E= 10, F=20

  4. E= 15, F=10

  5. E= 10, F=15
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Let present ages be 7x and 3x. E years ago: (7x - E) = 3(3x - E). F years hence: (7x + F) = 2(3x + F). Solving yields E = F = 10. Substitute back: 2x = 10, x = 5. Present ages: 35 and 21, ratio 7:3. Verify: 25 years ago, 10 and 6 (ratio 3:1). 10 years hence, 45 and 22.5 (ratio 2:1).

Keep practicing — related questions