Multiple choice

If a right circular cone of height 24 cm has a volume of 1232 cm3, then the area of its curved surface (Take π = 22/7 ) is यदि एक लम्बवृत्तीय शंकु की ऊँचाई 24 सेमी. तथा आयतन 1232 घन सेमी है तो उसके वक्रपृष्ठ का क्षेत्रफल है- (लिया गया है π = 22/7)

  1. 1254 cm2 /सेमी2

  2. 704 cm2 /सेमी2

  3. 550 cm2 /सेमी2

  4. 154 cm2 /सेमी2
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C Correct answer
Explanation

Cone volume = (1/3)πr²h = 1232. With h = 24, π = 22/7: (1/3)(22/7)r²(24) = 1232. Solving: r² = 49, r = 7. Slant height l = √(h² + r²) = √(576 + 49) = 25. Curved surface = πrl = (22/7) × 7 × 25 = 550 cm².

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