Multiple choice

Solve the following equations and find the values of (x) and (y): I. (4x^2 + 19x + 21 = 0) II. (15y^2 - 29y + 12 = 0)

  1. If X < Y

  2. If X > Y

  3. If X ≤ Y

  4. If X ≥ Y

  5. If X=Y or no relation can be established
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A Correct answer
Explanation

Equation I: 4x² + 19x + 21 = (4x+7)(x+3) = 0, so x = -7/4 or -3. Equation II: 15y² - 29y + 12 = 0 gives y = 4/3 or 3/5 (discriminant 121, sqrt 11). Since x values are -1.75 and -3, while y values are 0.6 and 1.33, every x is less than every y. Therefore X < Y is always true.

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