Multiple choice

In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer I. (4x^2 - 33x + 63 = 0) II. (10y^2 – 113y + 318 = 0)

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or no relation can be established between x and y
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Solve Equation I: 4x^2 - 33x + 63 = 0. Factors: (4x-21)(x-3) = 0. Solutions: x = 21/4 = 5.25 or x = 3. Solve Equation II: 10y^2 - 113y + 318 = 0. Using quadratic formula: y = [113 ± sqrt(12769 - 12720)]/20 = [113 ± sqrt(49)]/20 = [113 ± 7]/20. Solutions: y = 120/20 = 6 or y = 106/20 = 5.3. Comparing: x values are 3 and 5.25; y values are 5.3 and 6. The maximum x (5.25) is less than the minimum y (5.3), so x < y.

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