Multiple choice

In each of the following questions two equations (I) and (II) are given. Solve these equations and give the answer: (I). (x^2 - 14x + 24 = 0) (II). (y^2 - 3y + 2 = 0)

  1. If x < y

  2. If x > y

  3. If x ≥ y

  4. If x ≤ y

  5. If x = y or no relationship can be established between x and y.
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C Correct answer
Explanation

Solving equation I: x² - 14x + 24 = 0 factors to (x-12)(x-2) = 0, so x = 12 or 2. Solving equation II: y² - 3y + 2 = 0 factors to (y-2)(y-1) = 0, so y = 2 or 1. Comparing values: when x=12, x > both y values; when x=2, x = y=2 or x > y=1. Therefore x ≥ y is always true.

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