Multiple choice

In each of the following questions two equations (I) and (II) are given. Solve these equations and give the answer: ( (I) (x – 16)^2 = 0 ) ( (II) y^2 - 256 = 0 )

  1. $If \( x < y \)$
  2. $If \( x > y \)$
  3. $If \( x \ge y \)$
  4. $If \( x \le y \)$

  5. If x = y or no relationship can be established between x and y.
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Equation I: (x-16)²=0 gives x=16 (repeated root). Equation II: y²-256=0 gives y²=256, so y=16 or y=-16. Comparing: when y=16, x=16 gives x=y; when y=-16, x=16 gives x>y. In all cases x ≥ y, so option C is correct.

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