Multiple choice

In each of the following questions two equations (I) and (II) are given. Solve these equations and give the answer:( (I) ) (39x^2 - 61x + 16 = 0) ( (II) ) (15y^2 - 237y + 180 = 0)

  1. If x < y

  2. If x > y

  3. If x ≥ y

  4. If x ≤ y

  5. If x = y or no relationship can be established between x and y.
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E Correct answer
Explanation

Solving equation (I): 39x² - 61x + 16 = 0 gives x = 16/13 ≈ 1.23 or x = 1/3 ≈ 0.33. Solving equation (II): 15y² - 237y + 180 = 0 gives y = 15 or y = 4/5 = 0.8. Comparing the values: when x = 1/3 and y = 15, x < y; when x = 16/13 and y = 0.8, x > y. Since different root pairs give different relationships, no consistent relationship can be established.

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