Multiple choice

In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer. I. (x = \sqrt{256}) II. (y^2 - 32y + 97 = -159)

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or no relation can be established between x and y
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

For x = √256, we have x = 16. For y² - 32y + 97 = -159, rearrrange to y² - 32y + 256 = 0, which factors as (y - 16)² = 0, giving y = 16 (repeated root). Since x = 16 and y = 16, we have x = y. The relationship is x = y, not x > y or x < y, so the correct answer is that x = y (no relation needed).

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