Multiple choice

In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer. I. (2x^2 + 24x = -72) II. (y^2 = 36)

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or no relation can be established between x and y
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Rearrange 2x² + 24x = -72 to 2x² + 24x + 72 = 0, then divide by 2: x² + 12x + 36 = 0. Factor as (x + 6)² = 0, giving x = -6 (repeated root). For y² = 36, we get y = ±6, so y = 6 or y = -6. Since x = -6 and y can be 6 or -6, we have x = y when y = -6, and x < y when y = 6. Therefore x ≤ y holds in all cases.

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