Multiple choice

In each of these questions, two equations (I) and (II) are given. You have to solve both the equations and give answer I. 49x2 + 84x – 64 = 0 II. 25y2 – 100y + 64 = 0

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or no relation can be established between x and y
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Solve 49x² + 84x - 64 = 0 using the quadratic formula: x = (-84 ± √(7056 + 12544))/(98) = (-84 ± √19600)/98 = (-84 ± 140)/98. This gives x = -8/7 ≈ -1.14 or x = 16/7 ≈ 2.29. For 25y² - 100y + 64 = 0: y = (100 ± √(10000 - 6400))/50 = (100 ± √3600)/50 = (100 ± 60)/50. This gives y = 4/5 = 0.8 or y = 16/5 = 3.2. Since both x values are less than both y values, x < y is correct.

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