Multiple choice

In each of the following questions two equations (I) and (II) are given. Solve these equations and give the answer: (I) (-3x^2 + 5x + 42 = 0) (II) (-2y^2 + 9y + 35 = 0)

  1. $\(x > y\)$
  2. $\(x \ge y\)$
  3. $\(x < y\)$
  4. $\(x \le y\)$

  5. If x = y or no relationship can be established between x and y
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Rewrite equation (I) as 3x^2 - 5x - 42 = 0, which factors as (x - 7)(3x + 6) = 0, giving x = 7 or x = -2. Rewrite equation (II) as 2y^2 - 9y - 35 = 0, which factors as (y - 7)(2y + 5) = 0, giving y = 7 or y = -2.5. Comparing possible pairs: if x = -2 and y = 7, then x < y; if x = -2 and y = -2.5, then x > y; if x = 7 and y = 7, then x = y. Since the relationship changes based on which values you compare, no consistent relationship exists.

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