Multiple choice

In each of these questions, two equations (I) and (II) are given. You have to solve both equations to give the answer: ( (I) x^2 + 15x + 56 = 0 ) ( (II) y^2 - 256 = 0 )

  1. If x < y

  2. If x > y

  3. If x ≥ y

  4. If x ≤ y

  5. If x = y or no relationship can be established between x and y.
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E Correct answer
Explanation

Equation (I): x² + 15x + 56 = 0 factors to (x+7)(x+8)=0, so x = -7 or -8. Equation (II): y² - 256 = 0 gives y = +16 or -16. For x = -7 or -8 and y = -16, we have x > y. For x = -7 or -8 and y = 16, we have x < y. Since x can be greater or less than y depending on values, no definite relationship exists.

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