Multiple choice

In the following question two equation numbered I and II are given you have to solve both the equations and give answer. (I. ) (x^{2} – 4 = 0) (II. ) (y^{2} + 6y + 9 = 0)

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or the relationship cannot be established.

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A Correct answer
Explanation

Solving equation I: x^2 - 4 = 0 gives x = ±2. Solving equation II: y^2 + 6y + 9 = 0 gives (y + 3)^2 = 0, so y = -3 only. When x = 2, we have x > y (2 > -3). When x = -2, we also have x > y (-2 > -3). Therefore, x is always greater than y.