Multiple choice

In each of the following questions two equations are given. Solve these equations and give answer: (I) (x^2 - x - 42 = 0) (II) (y^2 - 7y + 12 = 0)

  1. x > y

  2. x ≥ y

  3. x < y

  4. x ≤ y

  5. If x = y or no relationship can be established between x and y.
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

For equation (I): x² - x - 42 = 0 factors to (x - 7)(x + 6) = 0, so x = 7 or x = -6. For equation (II): y² - 7y + 12 = 0 factors to (y - 3)(y - 4) = 0, so y = 3 or y = 4. Comparing all pairs: (7,3) gives x > y; (7,4) gives x > y; (-6,3) gives x < y; (-6,4) gives x < y. Since we get both x > y and x < y depending on which roots we compare, no consistent relationship can be established. Option E is correct.

Keep practicing — related questions