Multiple choice

In each of the following questions, two equations are given. You have to solve them and $I. (x^{2} + 19x + 78 = 0) II. (y^{2} + y - 72 = 0)$

  1. If x>y

  2. If x≥y

  3. If x<y

  4. If x≤y

  5. If x=y or relationship can not be established
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Solving x²+19x+78=0 gives x=-6 or x=-13. Solving y²+y-72=0 gives y=-9 or y=8. Comparing all possible pairs: when x=-6, y could be -9 (x>y) or 8 (x

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