Multiple choice

In this question two equations numbered I and II are given. You have to solve both the equations and state the correct relationship. $I. (12p^2 - 17p + 6 = 0) II. (q^2 - 16q + 63 = 0)$

  1. If p > q

  2. If p ≥ q

  3. If p < q

  4. If p ≤ q

  5. If p = q or no relation can be established.
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Equation I factors to (3p-2)(4p-3)=0, giving p=2/3 and p=3/4. Equation II factors to (q-7)(q-9)=0, giving q=7 and q=9. Since all values of p (0.67, 0.75) are less than all values of q (7, 9), p is always less than q.

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