(\text{In each of the following question, two equation (I) and (II) is given. You have to solve them and answer the question}\(I) 12x^2 + 11x + 12 = 10x^2 + 22x \qquad (II) 13y^2 – 18y + 3 = 9y^2 – 10y)

Simplify equation I: 12x² + 11x + 12 = 10x² + 22x gives 2x² - 11x + 12 = 0, which factors to (2x-3)(x-4) = 0, so x = 1.5 or 4. Simplify equation II: 13y² - 18y + 3 = 9y² - 10y gives 4y² - 8y + 3 = 0, which factors to (2y-1)(2y-3) = 0, so y = 0.5 or 1.5. Comparing: x values (1.5, 4) are greater than or equal to y values (0.5, 1.5).