Multiple choice

A train after travelling 90 km meets with an accident and then proceeds at (\frac{3}{4}) of its former speed and arrives at its destination 30 minutes late. Had the accident occurred 45 km further, it would have reached the destination only 20 minutes late. Find the total distance.

  1. 270 Km.

  2. 225 Km.

  3. 135 Km.

  4. 245 Km.

  5. None of these
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let the original speed be v. After accident at 90 km, the reduced speed (3v/4) causes 0.5 hour delay: (1/3)×(d-90)/v=0.5, so (d-90)/v=1.5. After accident at 135 km, delay is 1/3 hour: (1/3)×(d-135)/v=1/3, so (d-135)/v=1. Subtracting gives 45/v=0.5, hence v=90. Substituting: d-135=90, so d=225 km.

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