Multiple choice

In the given question two equations numbered (I) and (II) are given. You have to solve both the equations and give answer.\nI. (20p^2 + 31p + 12 = 0) \nII. (21q^2 - 23q + 6 = 0)

  1. If p > q

  2. If p < q

  3. If p ≥ q

  4. If p ≤ q

  5. If p = q or no relation between p and q can be established
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

For equation I: 20p² + 31p + 12 = 0 factors as (4p + 3)(5p + 4) = 0, giving p = -3/4 and p = -4/5. For equation II: 21q² - 23q + 6 = 0 factors as (3q - 2)(7q - 3) = 0, giving q = 2/3 and q = 3/7. Comparing the values: both roots of p (-3/4, -4/5) are less than both roots of q (2/3, 3/7). Therefore p < q.

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