Multiple choice

In each of the following questions, two equations are given. You have to solve them and answer the question. $(I.) (35x^{2} - 53x + 20 = 0) (II.) (56y^{2} - 97y + 42 = 0)$

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or relationship cannot be established
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

For 35x²-53x+20=0: factors as (5x-4)(7x-5)=0, so x = 4/5 = 0.8 or x = 5/7 ≈ 0.714. For 56y²-97y+42=0: factors as (7y-6)(8y-7)=0, so y = 6/7 ≈ 0.857 or y = 7/8 = 0.875. In all cases, x values are less than y values, so x < y.

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