Multiple choice

In each of the following questions, two equations are given. You have to solve them and answer the question. $( (I) x^{2} + 18x – 943 = 0 )( (II) y^{2} + 40y + 391 = 0 )$

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or relationship cannot be established.
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

For x²+18x-943=0: discriminant = 324+3772=4096, roots = (-18±64)/2 = 23, -41. For y²+40y+391=0: discriminant = 1600-1564=36, roots = (-40±6)/2 = -17, -23. Comparing: 23 > -17, -23 but -41 < -17, -23. Since the relationship varies, it cannot be established.

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