In each of the following questions, two equations are given. You have to solve them and answer the question.(\text{(I)}) (12x^2 + 22x + 8 = 0)(\text{(II)}) (4y^2 - y - 3 = 0)

For 12x²+22x+8=0: factorizing gives 2(6x²+11x+4)=0, then (2x+1)(3x+4)=0, so x = -1/2 or -4/3. For 4y²-y-3=0: factorizing gives (4y+3)(y-1)=0, so y = -3/4 or 1. Comparing: x=-0.5 or -1.33; y=-0.75 or 1. x=-0.5 > y=-0.75, x=-0.5 < y=1, x=-1.33 < y=-0.75, x=-1.33 < y=1. Since x is sometimes less than y and sometimes greater, the relationship cannot be established.