Multiple choice technology programming languages

What will happen if you try to compile and run this ? public class Test{ static{ print(10); } static void print(int x){ System.out.println(x); System.exit(0); } }

  1. Compiler error.

  2. Will throw a NoSuchMethod error at runtime.

  3. It will compile and run printing out "10"

  4. It will run with no output.

  5. It will run and print "10" and then crash with an error.
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

The code compiles and runs successfully. Static blocks are executed when the class is loaded, and static methods can be called from static blocks. The print(10) method is static, so it's accessible from the static block. The program prints "10" and then exits immediately due to System.exit(0).

AI explanation

To answer this question, let's analyze the code step by step:

The given code defines a class called "Test" with a static method called "print" that takes an integer argument.

In the static block of the class, the method "print" is called with an argument of 10.

When the code is compiled and executed, the static block will be executed before the main method. Therefore, the "print" method will be called with an argument of 10.

Inside the "print" method, the argument value is printed using System.out.println(x), which will print "10" to the console.

After printing the value, the System.exit(0) statement is encountered. This statement terminates the Java Virtual Machine (JVM) and the program execution stops.

Therefore, when the code is compiled and run, it will print out "10" and then terminate.

Based on this explanation, the correct answer is C) It will compile and run, printing out "10".

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