Multiple choice

In the given question two equations numbered I and II are given. You have to solve both the equations and give answer $(I. 12x^2 + 29x + 14 = 0 )(II. 12y^2 - 22y + 8 = 0)$

  1. If x > y

  2. If x < y

  3. If x ≥ y

  4. If x ≤ y

  5. If x = y or relation between x and y can't be established
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Equation I: 12x² + 29x + 14 = 0. Splitting 29x as 8x + 21x and factoring by grouping gives x = -2/3 or x = -7/4. Equation II: 12y² - 22y + 8 = 0. Simplifying: 6y² - 11y + 4 = 0 gives y = 1/3 or y = 2/3. For all x values, x < all y values, so x < y.

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