Multiple choice

In the given question two equations numbered I and II are given. You have to solve both the equations and give answer. (I. 4x^2 + x - 3 = 0 )(II. 6y^2 - 5y + 1 = 0)

  1. If x > y

  2. If x < y

  3. If x ≥ y

  4. If x ≤ y

  5. If x = y or realtion between x and y can't be established
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Equation I: 4x² + x - 3 = 0 gives x = 3/4 or x = -1. Equation II: 6y² - 5y + 1 = 0 gives y = 1/2 or y = 1/3. Comparing all pairs: when x = -1, x < both y values. When x = 3/4, x > both y values. No single relationship holds consistently.

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