Multiple choice

In each of the following questions, two equations are given. You have to solve them and give answer. $( (I) \ 3x + 2y - 58 = 0 )( (II) \ 4x + 4y = 92 )$

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or relationship can not be established

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Multiply equation (II) by 2: 8x + 8y = 184. Equation (I) is 3x + 2y = 58. Multiply equation (I) by 4: 12x + 8y = 232. Subtract: (12x+8y) - (8x+8y) = 232-184, giving 4x = 48, so x = 12. From equation (I): 36 + 2y = 58, so 2y = 22 and y = 11. Since x = 12 > y = 11, the answer is x > y.