Multiple choice

In each of the following question two equations are given. You have to solve both of the equations and give answer: I. (x^{2} – 0.1x – 0.12 = 0) II. (y^{2} + 0.9y + 0.20 = 0)

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or no relation can be established
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A Correct answer
Explanation

Equation I: x² - 0.1x - 0.12 = 0 factors to (x - 0.4)(x + 0.3) = 0, so x = 0.4 or x = -0.3. Equation II: y² + 0.9y + 0.20 = 0 factors to (y + 0.5)(y + 0.4) = 0, so y = -0.5 or y = -0.4. In all four combinations (0.4 vs -0.5, 0.4 vs -0.4, -0.3 vs -0.5, -0.3 vs -0.4), x > y.

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