Multiple choice

In each of the following question two equations are given. You have to solve both of the equations and give answer: I. (x^2 + x – 6 = 0) II. (y^2 + 3y – 10 = 0)

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or no relation can be established
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Equation I factors to (x + 3)(x - 2) = 0, giving x = -3 or x = 2. Equation II factors to (y + 5)(y - 2) = 0, giving y = -5 or y = 2. When x = 2, y can equal 2. When x = -3, y could be -5 (x > y) or 2 (x < y). Since no consistent relation exists, the answer is that either x = y or no relation can be established.

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