Multiple choice

$In each of the following questions two equations are given you have to solve them and (Give) (answer)$ $((I)) (x^2 + 2x – 3 = 0)()((II)) (y^2 – 6y + 9 = 0)$

  1. $If \(x > y\)$
  2. $If \(x < y\)$
  3. $If \(x = y\)$
  4. $If \(x \ge y\)$
  5. $If \(x \le y\)$
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Solving equation (I): x^2 + 2x - 3 = 0 factors to (x+3)(x-1) = 0, giving x = -3 or x = 1. Solving equation (II): y^2 - 6y + 9 = 0 factors to (y-3)^2 = 0, giving y = 3 (repeated root). Comparing the values: both values of x (-3 and 1) are less than y (3). Therefore, x < y is the correct relationship.

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