In a bag there are 4 white, 4 red and 2 green balls. Two balls are drawn at random.What is the probability that at least one ball is of red color? एक बैग में 4 सफेद, 4 लाल और 2 हरे रंग की गेंद होती हैं। दो गेंदें यादृच्छिक रूप से चुनी जाती हैं। क्या प्रायिकता है कि कम से कम एक गेंद लाल रंग की हो?

Total balls = 4 + 4 + 2 = 10. Drawing 2 balls at random gives C(10,2) = 45 total outcomes. 'At least one red' means 1 red OR 2 reds. Cases: (i) 1 red, 1 non-red: C(4,1)×C(6,1) = 4×6 = 24. (ii) 2 reds: C(4,2) = 6. Total favorable = 24 + 6 = 30. Probability = 30/45 = 2/3. Alternatively, P(at least 1 red) = 1 - P(no red) = 1 - C(6,2)/C(10,2) = 1 - 15/45 = 30/45 = 2/3.