Multiple choice

One year ago Naveen’s father was 2 times as old as Praveen, but 20 years later from now Praveen’s father will be 1 year less than 2.5 times of Naveen’s present age. How many years old is their (Naveen and Praveen) father now, if the age difference between both the brothers (Naveen > Praveen) is 2 years?

  1. 58 years

  2. 69 years

  3. 79 years

  4. 59 years
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Let present ages: Naveen = N, Praveen = P, Father = F. Given N = P + 2. One year ago: F-1 = 2(P-1), so F = 2P - 1. 20 years later: F+20 = 2.5N - 1, so F = 2.5N - 21. Equating: 2P - 1 = 2.5(P+2) - 21. Solving: 2P - 1 = 2.5P + 5 - 21, so 2P - 1 = 2.5P - 16, giving 0.5P = 15, so P = 21, N = 23, F = 2(21)-1 = 41. Wait - recalculating carefully: 2P - 1 = 2.5(P+2) - 21 gives 2P - 1 = 2.5P + 5 - 21 = 2.5P - 16. So 15 = 0.5P, P = 30, N = 32, F = 2(30)-1 = 59. The father is 59 years old.

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