Multiple choice

In each of the following questions, two equations are given. You have to solve them and give answer- $I. (2p^2 + 15p = 27) II. (3q^2 + 23q = 36)$

  1. If p = q or relationship can’t be established

  2. If p > q

  3. If q > p

  4. If p ≥ q

  5. If q ≥ p
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Solving 2p² + 15p = 27 gives 2p² + 15p - 27 = 0, so (2p-3)(p+9) = 0, meaning p = 3/2 or p = -9. Solving 3q² + 23q = 36 gives 3q² + 23q - 36 = 0, so (3q-4)(q+9) = 0, meaning q = 4/3 or q = -9. Comparing: p=1.5 > q≈1.33, p=1.5 > q=-9, p=-9 = q=-9. In all valid cases, p ≥ q holds.

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