Multiple choice

In each of the following questions, two equations (I) and (II) are given. You have to solve them and answer the given question. $I. (x^{2} - 24x + 144 = 0) (II. 2y^{2} - 52y + 338 = 0)$

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or relationship cannot be established

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Solve equation I: x² - 24x + 144 = 0 can be factored as (x-12)² = 0, giving x = 12. Solve equation II: 2y² - 52y + 338 = 0, divide by 2 to get y² - 26y + 169 = 0, which factors as (y-13)² = 0, giving y = 13. Since 12 < 13, x < y is the correct relationship.