Multiple choice

In the following questions two equations numbered I and II are given. You have to solve both the equations and given answer if $I. (p^2 - 15p + 56 = 0)$ $II. (q^2 + 4q - 96 = 0)$

  1. If p > q

  2. If p ≥ q

  3. If p < q

  4. If p ≤ q

  5. If p = q or no relation between p and q can be established
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Factor I: p²-15p+56 = (p-7)(p-8) = 0, so p = 7 or p = 8. Factor II: q²+4q-96 = (q+12)(q-8) = 0, so q = -12 or q = 8. Comparing all values: p=7 gives p-12), p=8 gives p=q when q=8, but p>q when q=-12. Since no single relation always holds, the answer is 'no relation can be established'.

Keep practicing — related questions