Multiple choice

In each of these question two equations numbered I and II are given. You have to solve both the equations and give answer if - I. (p^{2} + 7p + 12 = 0) II. (q^{2} + 6q + 8 = 0)

  1. $\(p < q\)$
  2. $\(p > q\)$
  3. $\(p \leq q\)$
  4. $\(p \geq q\)$

  5. p = q or no relation between p and q can be established
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

For equation I: p² + 7p + 12 = 0 factors to (p+3)(p+4) = 0, giving p = -3 or -4. For equation II: q² + 6q + 8 = 0 factors to (q+2)(q+4) = 0, giving q = -2 or -4. Comparing all combinations: when p=-3,q=-2 we get pq; when p=-4,q=-2 we get p

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